PIYUSH FORMULA AND TABLE FOR TWO DIGIT SQUARE ,IT IS NEW METHOD ,SEARCH BY PIYUSHDADRIWALA
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N2 2 = 0+(20n1 -19) n+ (2n-2) n
2
N2 2 = 100+(20n1 -19) n+ (2n-2) n
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N2 2 = 400+(20n1 -19) n+ (2n-2) n
2
N2 2 = 900+(20n1 -19) n+ (2n-2) n
2
For Example
(1) 222 = 400 +(22 * 3 -19) 2+ (2*2-2)/2)2
= 400 +(60 -19)2 +((4-2)/2)2
=400 +(41*2)+(2/2)2
=400 +82 +2
=400+84
=484
(2) 112 = 100 +(20 * 2 -19) 1+ (2*1-2)/2)2
= 100 +40 -19 +0
=100 +21
=121
Note : n1=2 and n2=11
(3) 252 = 400 +(20 * 3 -19) 5+ ((2*5-2)/2)5
= 400 +(60 -19 )5+20
=400 +41*5+20
=420+205
=625
(4) 92 = 0 +(20 n 1 -19) n+ ((2 n-2)/2)n
= 0+(20 * 10 -19)9+ ((2* 9 -2)/2)9
=0+(200-19)9+(16/2)9
=0+(
(5) 112 = 100 +(20 * 2 -19) 1+ (2*1-2)/2)2
= 100 +40 -19 +0
=100 +21
=121
Playing with Pascal's Triangle, part 1
15 years ago
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