"(PIYUSH CONSTANT)

SUM OF EACH DIGIT REMAINS "9"(PIYUSH CONSTANT)
Fri, 2006-07-21 22:34 — piyushdadriwala
SUM OF EACH DIGIT REMAINS SAME(9),NINE
I AM VERY MUCH FOND OF MATHS ,WHATEVER I AM WRITING HERE IS AMAZING,INTERESTING,LEARN IT,VERY SIMPLE.(FOR ANY NO OF DIGITS)
NOW,I HAVE 25 AND 32, MULTIPLE THEM ,NOW YOU CAN MULTIPLE THEM IN FOUR WAYS LIKE THAT(just changing the position)
25*32=800
52*32=1664
25*23=575
52*23=1196
now substract any bigger to any lower you will always get sum of each digit nine.
1664-1196=468(4+6+8=18=1+8=9)
1664-800=864(8+6+4+18=1+8+=9)
1664-575=1089(1+0+8+9=18=1+8=9)
1196-800=396(3+9+6=18=1+8=9)
1196-575=621(6+2+1=9)
800-575=225(2+2+5=9).
this i called "piyush contant"
with lot of regards
piyushdadriwala
www.piyush-g.741.com
pkgdwala@rediffmail.com
in the next topic"what all GODS HAVE COMMON".

www.piyushdadriwalamaths.co.in